Chemistry : Chemistry Question

Hello,

I have a stoichiometry question which I answered incorrectly and I am not sure where I went wrong...the question is as follows:

Urea [(NH2)2 CO] is used for fertilizer and many other things. Calculate the number of N, C, O, and H atoms in 1.68 * 10^4 g of urea.

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First, I found the total atomic weights of each element in this compound to find the percent composition:

N: 28.02 amu

H: 4.032 amu

C: 12.01 amu

O: 16 amu

Total atomic weight of urea: 60.062

Then, I found the percent composition of urea:

N: 46.65%

H: 6.71%

C: 20.00%

O: 26.64%

Then, I converted 1.68 * 10^4 grams into moles by dividing this amount in grams by 60.062, and found that it is approximately 279.71 moles.

After that, I took percentages of this to calculate the number of moles of each element in the sample of urea (for example, 46.65% of 279.71 to find the number of moles of nitrogen).

Finally, I multiplied each of these numbers in moles by Avogadro's number (6.022 * 10^23) to obtain the number of atoms. However, when I checked my answers in my textbook, I was wrong by a significant amount.

My answers: 7.83 * 10^25 atoms N, 1.13 * 10^25 atoms H, 3.37 * 10^25 atoms C, 4.49 * 10^25 atoms O

The correct answer: 3.37 * 10^37 atoms N, 1.69 * 10^26 atoms C, 1.69 * 10^26 atoms O, 6.74 * 10^26 atoms H

Do you know where I am going wrong? Thank you very much!

Answers

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